Let’s say I have the formula Y(n+1)= λ*Y(n)(1-Y(n)) So the value of Y at time n+1 is some factor (λ) times Y at time n times 1 minus Y at time n. Y is between 0 and 1. λ can be anything. As a starting point I choose Y0 to be 0.5 and λ=1. (In […]

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